172 Divided By 15 172 172
I would have put 1010 1100 representing 172 You are right and the solution sheet is wrong Probably just a typo on the part of whoever wrote the solution sheet also don t 172 127 WindowsXP IP 127 0 0 1 IP
172 Divided By 15
172 Divided By 15
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172 16 0 0 12 192 168 0 0 16 You are free to use any or all the Private IP addressing in your own private network but you cannot use any addresses in any of the three Private address 172 huang 172
LYKINS 1861 show ip arp 172 20 1 100 Protocol Address Age min Hardware Addr Type Interface Internet 172 20 1 100 0 28cf da1d 1b05 ARPA Vlan10 Now log into the Layer 2 2011 1
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The first address in the subnet 178 18 230 120 is the Network Address in this case and the last address which is all 1 s i e 172 18 230 127 is the Broadcast Address The host address can 180 182 183 185 175 173 184 183 182 178 177 172 181
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I would have put 1010 1100 representing 172 You are right and the solution sheet is wrong Probably just a typo on the part of whoever wrote the solution sheet also don t
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172 Divided By 15 - [desc-13]
