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I would have put 1010 1100 representing 172 You are right and the solution sheet is wrong Probably just a typo on the part of whoever wrote the solution sheet also don t 172 127 WindowsXP IP 127 0 0 1 IP

172 Divided By 16

half-brain-half-heart-with-flowers-coloring-book-art-line-art

172 Divided By 16
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107351667-17036185662023-06-16t140748z-1184483635-rc2dk1ajdn3n-rtrmadp

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172 16 0 0 12 192 168 0 0 16 You are free to use any or all the Private IP addressing in your own private network but you cannot use any addresses in any of the three Private address 172 huang 172

LYKINS 1861 show ip arp 172 20 1 100 Protocol Address Age min Hardware Addr Type Interface Internet 172 20 1 100 0 28cf da1d 1b05 ARPA Vlan10 Now log into the Layer 2 2011 1

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The first address in the subnet 178 18 230 120 is the Network Address in this case and the last address which is all 1 s i e 172 18 230 127 is the Broadcast Address The host address can 180 182 183 185 175 173 184 183 182 178 177 172 181

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https://www.zhihu.com › question
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107351667 17036185662023 06 16t140748z 1184483635 rc2dk1ajdn3n rtrmadp
What Range Of IP Addresses Is Represented By The CIDR Block

https://networkengineering.stackexchange.com › questions
I would have put 1010 1100 representing 172 You are right and the solution sheet is wrong Probably just a typo on the part of whoever wrote the solution sheet also don t


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172 Divided By 16 - 172 huang 172