9x 3 6x 2 28x 9 Divided By 3x 1 07 02 mc the lengths of two sides of a triangle are shown below side 1 3x2 2x 1 side 2 9x 2x2 3 the perimeter of the triangle is 5x3 4x2 x 3 part a what is the total
131 9x APP To form a quadratic polynomial with zeroes a 1 and 1 given that a and are the zeroes of the polynomial x 9x 20 we can start by using Vieta s formulas Vieta s
9x 3 6x 2 28x 9 Divided By 3x 1
9x 3 6x 2 28x 9 Divided By 3x 1
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8s 9x 8s 9x 9x 2 25 0 2 225 9x 2 225 x 2 225 9 x 225 9 x 15 3 x 5 So the limits of integration for x are 5 to 5 Now we can set up the integral to find the area A x 5 to 5
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07 02 mc the lengths of two sides of a triangle are shown below side 1 3x2 2x 1 side 2 9x 2x2 3 the perimeter of the triangle is 5x3 4x2 x 3 part a what is the total


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9x 3 6x 2 28x 9 Divided By 3x 1 - [desc-14]