Int Byte Size The C standard does not specify the size of integral types in bytes but it specifies a minimum width in bits see basic types fundamental p1 You can infer minimum size in bytes from that and the value of the CHAR BIT macro that defines the number of bits in a byte In all but the most obscure platforms it s 8 and it can t be less than 8 One additional constraint for char is that its
The only real difference here is the size All of the int types here are signed integer values which have varying sizes Int16 2 bytes Int32 and int 4 bytes Int64 8 bytes There is one small difference between Int64 and the rest On a 32 bit platform assignments to an Int64 storage location are not guaranteed to be atomic It is guaranteed for all of the other types The size of integer is basically depends upon the architecture of your system Generally if you have a 16 bit machine then your compiler will must support a int of size 2 byte If your system is of 32 bit then the compiler must support for 4 byte for integer In more details The concept of data bus comes into picture yes 16 bit 32 bit means nothing but the size of data
Int Byte Size
Int Byte Size
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What is the difference between tinyint smallint mediumint bigint and int in MySQL In what cases should these be used The size of char in bits isn t specified explicitly either although sizeof char is defined to be 1 If you want a 64 bit int C 11 specifies long long to be at least 64 bits
E g int 10 1 byte int 257 2 bytes My question is why does 10 require 1 byte and why does 257 require 2 From what I understand you can represent 10 as 1010 which is 4 bits and 257 as 100000001 which is 9 bits Does it have to do with word size This is a bit of a general question and not completely related to the c programming language but it s what I m on studying at the moment Why does an integer take up 4 bytes or How ever many bytes
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4 Two types with the same size in bytes can have different ranges for sure For example signed int and unsigned int are both 4 bytes but one has one of its 32 bits reserved for the sign which lowers the maximum value by a factor of 2 by default Also the range is different because the one can be negative How can I find out the number of Bytes a certain integer number takes up to store E g for hexadecimal x00 xff or decimal 0 255 binary 0000 0000 1111 1111 I m looking to get 1 Byte
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The C standard does not specify the size of integral types in bytes but it specifies a minimum width in bits see basic types fundamental p1 You can infer minimum size in bytes from that and the value of the CHAR BIT macro that defines the number of bits in a byte In all but the most obscure platforms it s 8 and it can t be less than 8 One additional constraint for char is that its
https://stackoverflow.com › questions
The only real difference here is the size All of the int types here are signed integer values which have varying sizes Int16 2 bytes Int32 and int 4 bytes Int64 8 bytes There is one small difference between Int64 and the rest On a 32 bit platform assignments to an Int64 storage location are not guaranteed to be atomic It is guaranteed for all of the other types
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