Half Circle Area Formula

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Half Circle Area Formula In polar co ordinates r a and alpha theta alpha pi The polar equation of a full circle referred to its center as pole is r a The range for theta for the full circle is pi For half circle the range for theta is restricted to pi So the answer is r a and alpha theta alpha pi where a and alpha are constants for the chosen half circle

If given the area The normal area of a circle is A pir 2 Since a semicircle is just half of a circle the area of a semicircle is shown through the formula A pir 2 2 We can solve for r to show an expression for the radius of a semicircle when given the area A pir 2 2 2A pir 2 2A pi r 2 r sqrt 2A pi If given the diameter The diameter like in a normal circle is just If you divide a circle into a number of equal segments then stack them in a row head to tail the resulting shape is like a parallelogram with bumpy sides with the same area as the circle As you make the segments smaller and smaller the parallelogram becomes more of a rectangle with shorter side equal to the radius of the circle r and longer side pi r half of the

Half Circle Area Formula

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When a circle is completely inscribed within a circle the radius of that particular circle is half the side of the square So in this case The radius r 4 2 2cm assuming the unit to be in cm Area of a circle is given by formula color blue pir 2 Where pi is of constant value 3 14 So area color blue pir 2 3 14 2 2 Half it to find the radius and then use the formula A pi r 2 to find the area The formula for the area of a circle is A pir 2 where A is the area and r is the radius Since we only know the diameter we need to figure out the radius Since the radius is always half the diameter we now know that the radius is 17mm and that means we know that r 17 Now we simply

The area of a circle is given by formula color blue pir 2 Where pi has a constant value of 3 14 r denotes the radius of the circle The radius of the circle is half the diameter 24 2 12cm assuming the unit to be in cm The area pir 2 3 14 xx 12 2cm 2 3 14 xx 144 452 16 cm 2 approxcolor blue 452 cm 2 The formula for the area of a circle is given by A pir 2 Where r is the radius and pi is the ratio of the circumference of a circle to its diameter Let D diameter and r radius Since the radius is half the diameter the radius is D 2 If the diameter increases by a factor bba Then the radius increases by a factor a 2

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Use the formula A pi r 2 Area 56 25 pi m or 225 4 pi m or approximately 176 7 m The formula for the area of a circle is A pi r 2 where A is the area and r is the radius The radius if half the diameter so r 1 2 d r 1 2 15m r 7 5m Therefore A pi r 2 A pi 7 5 2 A 56 25 pi m or A 176 7 m correct to 1 decimal place Pixx semi major axis xx semi minor axis Similar to how the area of a circle is A pir 2 an oval ellipse is similar except for that it has the equivalent of two radii the semi minor and semi major axes The r 2 in the circle area equation is replaced with the product of the lengths of the axes A ellipse piab

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In polar co ordinates r a and alpha theta alpha pi The polar equation of a full circle referred to its center as pole is r a The range for theta for the full circle is pi For half circle the range for theta is restricted to pi So the answer is r a and alpha theta alpha pi where a and alpha are constants for the chosen half circle

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If given the area The normal area of a circle is A pir 2 Since a semicircle is just half of a circle the area of a semicircle is shown through the formula A pir 2 2 We can solve for r to show an expression for the radius of a semicircle when given the area A pir 2 2 2A pir 2 2A pi r 2 r sqrt 2A pi If given the diameter The diameter like in a normal circle is just


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Half Circle Area Formula - Half it to find the radius and then use the formula A pi r 2 to find the area The formula for the area of a circle is A pir 2 where A is the area and r is the radius Since we only know the diameter we need to figure out the radius Since the radius is always half the diameter we now know that the radius is 17mm and that means we know that r 17 Now we simply